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Measure of two quantites along with the ...

Measure of two quantites along with the precision of respective measuring instrument is `A = 2.5 ms^(-1) +- 0.5 ms^(-1)`
`B = 0.10 s +- 0.01s` The value of AB will be

A

`(0.25 pm 0.08)m`

B

`(0.25 pm 0.5)m`

C

`(0.25 pm 0.05)m`

D

`(0.25 pm 0.135)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`A = 2.5 ms^(-1) pm 0.5ms^(-1), B = 0.10 s pm 0.01 s`
`x = AB = (2.5)(0.10) = 0.25m`
`(Deltax)/x = (DeltaA)/A +(DeltaB)/B`
`=(0.5)/(2.5)+(0.01)/(0.10)=(0.05+0.025)/(0.25)=(0.075)/(0.25)`
`Delta x =0.075 = 0.08m` , rounding off two significant figures `AB = (0.25 pm 0.08)m.`
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