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A physical parameter a can be determined...

A physical parameter `a` can be determined by measuring the parameters `b, c, d, and e` using the relation `a=b^(alpha)c^(beta)//d^(gamma)e^(delta)`. If the maximum errors in the measurement of `b, c , d, and e are b_(1) %,c_(1)% ,d_(1)% , and e_(1) %`, then the maximum error in the value of `a` determined by the experminent.

A

`(b_1 +c_1 +d_1+e_1) %`

B

`(b_1 +c_1 -d_1-e_1) %`

C

`(alphab_1 -betac_1 -gammad_1-deltae_1) %`

D

`(alphab_1 +betac_1 +gammad_1+deltae_1) %`

Text Solution

Verified by Experts

The correct Answer is:
D
`a=(b^(alpha)c^(beta))/(d^(gamma)e^(delta))`
`implies ((Deltaa)/a)xx100=(alpha(Deltab)/b +beta(Deltac)/(c) +gamma(Deltad)/d+delta(Deltae)/(e))xx100`
`=(alphab_1 + betac_1 + gammad_1 + deltae_1)%`
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