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The specific resistance rho of a thin wi...

The specific resistance `rho` of a thin wire of radius r cm, resistance R ohm and length L is given by `rho = (pi r^2R)/(L). If L =78+-0.01cm` `r = 0.26 +- 0.02 and R =32 +- 1 Omega,` What is the percentage error in `rho?`

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The correct Answer is:
18
The percentage error in specific resistance `sigma` is given by
`(Deltasigma)/(sigma)xx100 =(2 (Deltar)/(r)+(DeltaR)/(R)+(DeltaL)/L)xx100`
`=[(2 xx0.02 )/(0.26) +1/32 +(0.01)/78]xx100`
`= [0.15 +0.03+0.0001]xx100`
`= 0.1801xx100 = 0.18xx100 = 18%`
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