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A student performs an experiment for det...

A student performs an experiment for determination of `g = (4pi^(2) l)/(T^2)` and he commits an error of `Delta l `. For that he takes the time of n oscillations with the stop watch of least count `Delta T` and the commits a human error of 0.1 sec. For which of he following data, the measurement of g will be most accurate?

A

`{:(DeltaI,DeltaT,n,"Ampli. of oscill."),(5mm,0.2 sec, 10 , 5mm):}`

B

`{:(DeltaI,DeltaT,n,"Ampli. of oscill."),(5mm,0.2 sec, 20 , 5mm):}`

C

`{:(DeltaI,DeltaT,n,"Ampli. of oscill."),(5mm,0.1 sec, 20 , 1mm):}`

D

`{:(DeltaI,DeltaT,n,"Ampli. of oscill."),(1mm,0.1 sec, 50 , 1mm):}`

Text Solution

Verified by Experts

The correct Answer is:
D
For best result amplitude of oscillation should be a small as possible and more oscillation should be taken.
In (d) option, `DeltaI rarr` least, `DeltaT rarr` lea.
Amplitude of oscillation has least value and no. of oscillation is more.
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