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The diameter of a cylinder is measured u...

The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between `5.10cm and 5.15cm` of the main scale. The Vernier scale has `50` divisions equivalent to `2.45 cm`. The `24^(th)` division of the Vernier scale exactly coincides with one of the main scale divisions. the diameter of the cylinder is

A

5.112 cm

B

5.124 cm

C

5.136 cm

D

5.148 cm

Text Solution

Verified by Experts

The correct Answer is:
B
50 VSD=2.45 cm
`implies 1 VSD = (2.45)/50 cm = 0.049cm`
L.C. = 1MSD - 1VSD
`= 0.05 cm -0.049 cm = 0.001 cm`
Thickness of the object = Main scale reading + vernier scale reading `xx` L.C. `=5.10+24(0.001) = 5.124` cm.
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