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A particle moves in a circular orbit und...

A particle moves in a circular orbit under the action of a central attractive force inversely proportional to the distance `r`. The speed of the particle is

A

Proportional to `r^(2)`

B

Independent of r

C

Proportional to r

D

Proportional to `1//r`

Text Solution

Verified by Experts

The correct Answer is:
B
Let .F. be the force.
Given `F prop alpha 1/r`
`= F = k/r`, where k is a constant.
Since, particle experiences centripetal force.
`(mv^(2))/r = k/r`
`=v = sqrt(k/m)` (independent of r)
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