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A stone tied to the end of a string 1m l...

A stone tied to the end of a string 1m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolution in 44 seconds, what is the magnitude and direction of acceleration of the stone

A

`pi^(2)//4 ms^(-2)` and direction along the radius towards the centre

B

`pi^(2) ms^(-2)` and direction along the radius away from the centre

C

`pi^(2) ms^(-2)` and direction along the radius towards the centre

D

`pi^(2) ms^(-2)` and direction along the tangent to the circle

Text Solution

Verified by Experts

The correct Answer is:
C
r = 1m, frequency(f) `=22/44 = 1/2` sec
acceleration (a) `=v^(2)/r = omega^(2)r = (2pi f)^(2) xx r`
`= 4pi^(2) xx (1/2)^(2) xx 1 = pi^(2) m//s^(2)`
directed toward centre.
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