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If a particle covers half the circle of ...

If a particle covers half the circle of radius R with constant speed then

A

Change in momentum is mvr

B

Change in K.E. Is `1//2 mv^(2)`

C

Change in K.E. is `mv^(2)`

D

Change in K.E. is zero

Text Solution

Verified by Experts

The correct Answer is:
D
Change in momentum,
`DeltaP = -mv - mv =-2mv`

But kinetic energy remains constant, as change in K.E. is zero.
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