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If a cycle wheel of radius 4 m completes...

If a cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be

A

`pi^(2) m//s^(2)`

B

`2pi^(2) m//s^(2)`

C

`4pi^(2) m//s^(2)`

D

`8pi m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`a = omega^(2)r = 4pi^(2) (1/2)^(2) xx 4 = 4pi^(2) m//s^(2)`
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