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An object moves at a constant speed alon...

An object moves at a constant speed along a circular path in a horizontal `XY` plane, with the center at the origin. When the object is at `x=-2m`, its velocity is `-(4m//s)hatj`. What is the object's acceleration when it is `y=2m`

A

`-(8m//s^(2))`

B

`-(8m//s^(2))`

C

`-(4 m//s^(2))hatj`

D

`(4 m//s^(2))hati`

Text Solution

Verified by Experts

The correct Answer is:
A
`r = 2m, v = 4 m//s`
`a = v^(2)/r = 16/2 = 8 m//s^(2)`
when y = 2m, `a = (-8 m//s^(2))hatj`
because acceleration is directed towards centre.
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