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The length of second's hand in watch is ...

The length of second's hand in watch is `1 cm`. The change in Velocity of its tip in 15 seconds is

A

Zero

B

`pi/(30sqrt(2))` cm/sec

C

`pi/30` cm/sec

D

`(pisqrt(2))/30` cm/sec

Text Solution

Verified by Experts

The correct Answer is:
D
`theta = 90^(@)`
Charge in velocity `=|Deltavecv| = 2v sin (theta//2)`
`= 2(romega) sin 45^(@)`
`= 2 xx r xx (2pi)/7 sin 45^(@)`
`= 2 xx r xx (2pi)/T sin 45^(@)`
`= (4pi)/(60sqrt(2)) cm/"sec" = (pisqrt(2))/30` cm/s
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