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A particle moves in a circular orbit und...

A particle moves in a circular orbit under the action of a central attractive force inversely proportional to the distance `r`. The speed of the particle is

A

`r^(1//2)`

B

r

C

`r^(3//2)`

D

`r^(2//3)`

Text Solution

Verified by Experts

The correct Answer is:
B
Since, `(mv^(2))/r = k/r rArr v = sqrt(k/m)`
`T = (2pi)/v = 2pir sqrt(m/k) rArr T prop r`.
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