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Three identical particles are joined tog...

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is `v_(0)`, then the ratio of tensions in the three sections of the string is `(T_(BC):T_(AB):T_(DA))`

A

`3:5:7`

B

`3:4:5`

C

`7:11:6`

D

`3:5:6`

Text Solution

Verified by Experts

The correct Answer is:
D
`T_(3) = m omega^(2) (3l)`

`T_(2) - T_(3) = m omega^(2) (3r)`
`T_(1) - T_(2) = momega^(2)( r)`
`rArr T_(1) = momega^(2) (4r)`
`T_(1):T_(2) = 4:3`
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