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A particle is moving on a circular path ...

A particle is moving on a circular path of radius 30cm. Its linear speed is v = 2t, here t is time in second and v is in m/s. Calculate its centripetal acceleration and tangential acceleration at t = 3 sec.

A

`220 m//"sec"^(2), 50 m//"sec"^(2)`

B

`100 m//"sec"^(2), 5 m//"sec"^(2)`

C

`120 m//"sec"^(2), 2 m//"sec"^(2)`

D

`110 m//"sec"^(2), 10 m//"sec"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`v = 2t`
`a_(t) = (dv)/(dt) = 2 m//s^(2)`
`a_(r) = v^(2)/r rArr a_(r) , t = 3 sec = [2(3)]^(2)/0.3 = 36/0.3 =120 m//s^(2)`
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