Home
Class 11
PHYSICS
A particle is moving in a vertical circl...

A particle is moving in a vertical circle with constant speed. The tansions in the string when passing through two positions at angles `30^@` and `60^@` from vertical (lowest position) are `T_1` and `T_2` respectively. Then

A

`T_(1) =T_(2)`

B

`T_(2) gt T_(1)`

C

`T_(1) gt T_(2)`

D

Tension in the string always remains the same

Text Solution

Verified by Experts

The correct Answer is:
C

Since, `T - mg cos theta = (mv^(2))/r`
`rArr T = (mv^(2))/r + mg cos theta`
For `theta = 30^(@), T_(1) = (mv^(2))/r + (mgsqrt(3))/2`
Hence, `T_(1) gt T_(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is moving in a vertical in a vertical circle . The tensions in the string when passing through two positions at angles 30^(@) and 60^(@) from the lowest positon are T_(1) and T_(2) respectively , then

For a particle moving in vertical circle, the total energy at different positions along the path

A particle is moving in a vertical circle with radius 1 m. It the ratio of T_(max)/T_(min) =5 find the velocity at highest point ?

The tension in the string revolving in a vertical circle with a mass m at the end which is at the lowest position

A particle is projected so as to just move along a vertical circle of radius r. The ratio of the tension in the string when the particle is at the lowest and highest point on the circle is -

If a particle is moving on a circular path with constant speed, then the angle between the direction of acceleration and its position vector w.r.t. centre of circle will be

A particle is moving in a circle of radius R with constant speed. The time period of the particle is T. In a time t=(T)/(6) Average speed of the particle is ……

A particle is moving in a circle of radius R with constant speed. The time period of the particle is T. In a time t=(T)/(6) Average velocity of the particle is…..