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Two bodies are thrown up at angles of 45...

Two bodies are thrown up at angles of `45^(@)` and `60^(@)`, respectively, with the horizontal. If both bodies attain same vertical height, then the ratio of velocities with which these are thrown is

A

`sqrt(2/3)`

B

`2/sqrt(3)`

C

`sqrt(3/2)`

D

`sqrt(3)/2`

Text Solution

Verified by Experts

The correct Answer is:
C
`H = (u^(2) sin^(2) theta)/(2g)`
Since, `H_(1) = H_(2) rArr (u_(1)^(2) sin^(2) 45^(@))/(2g) = (u_(2)^(2) sin^(2) 60)/(2g)`
`rArr (3/4 xx 2/1) rArr u_(1)/u_(2) = sqrt(3/2)`
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