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The height y and the distance x along th...

The height `y` and the distance `x` along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by `y = (8t - 5t^2) m` and `x = 6tm`, where `t` is in seconds. The velocity with which the projectile is projected at `t = 0` is.

A

8m/sec

B

6m/sec

C

10m/sec

D

Not obtainable from the data

Text Solution

Verified by Experts

The correct Answer is:
C
`y = (8t -5t^(2)), x = 6t`
`v_(y) = (dy)/(dt) = 8-10 t, v_(x) = (dx)/(dt) = 6`
at t = 0
`u = sqrt(u_(x)^(2) + u_(y)^(2)) = sqrt(6^(2) + 8^(2)) = 10 m//s`
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