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A body is projected horizontally with a ...

A body is projected horizontally with a velocity of `u ms^(-1)` at an angle `theta` with the horizontal. The kinetic energy at the highest point is `(3)/(4)th` of the kinetic energy. The value of `theta` is :

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`120^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(KE_(1))/(KE_(2)) = 4/3 rArr (1/2 mu^(2))/(1/2 m(u cos beta)^(2)) = 4/3`
`rArr 3u^(2) =4u^(2) cos^(2)beta`
`rArr cos^(2)beta = 3/4 rArr cosbeta = sqrt(3/4)`
`rArr cos beta = sqrt(3)/2 rArr beta = 30^(@)`
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