Home
Class 11
PHYSICS
A body is projected vertically upwards a...

A body is projected vertically upwards at time "t=0" and it is seen at a height H at instants t_(1) and t_(2)seconds during its flight.The maximum height attained is (g is acceleration due to gravity

A

`(g(t_(2) - t_(1))^(2))/8`

B

`(g(t_(1) + t_(2))^(2))/4`

C

`(g(t_(1)+ t_(2))^(2))/8`

D

`(g(t_(2) - t_(1))^(2))/4`

Text Solution

Verified by Experts

The correct Answer is:
C
`t_(2) = t_(1) + 2t^(.)`
`rArr t^(.) =(t_(2)-t_(1))/2`
Total time taken, to reach point C
`T = t_(1) + t^(.) = t_(1) + (t_(2) - t_(1))/2`
`=(2t_(1) + t_(2) - t_(1))/2 = (t_(1) + t_(2))/2`
Then maximum height attained
`H_("max") =1/2 g(T)^(2) = 1/2 g((t_(1) + t_(2))/2)^(2) = 1/2 g(t_(1) + t_(2))^(2)/4`
`H_("max") = 1/8 g(t_(1) + t_(2))^(2)m`
Promotional Banner

Similar Questions

Explore conceptually related problems

A body is thrown vetically upward at t = 0 . It is at a height 80 m at two instant t_(1) and t_(2) , then t_(1) t_(2) is: (Take g = 10 m//s^(2) )

A stone is projected vertically upwards.When it reaches half the maximum height,its velocity is 20m/s.What is the maximum height attained by the stone? (g=10m/s^(2)

A body is projected vertically upwards from the surface of a planet of radius R with a velocity equal to hall the escape velocity for that planet. The maximum height attained by the body is

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A stone projected vertically up from the ground reaches a height y in its path at t_(1) seconds and after further t_(2) seconds reaches the ground. The height y is equal to

A particle is projected with a velocity v so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is