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A body is projected with a velocity of 2...

A body is projected with a velocity of `20 ms^(-1)` in a direction making an angle of `60^(@)` with the horizontal. Determine its (i) position after 0.5 s and (ii) the velocity after `0.5s`.

Text Solution

Verified by Experts

The correct Answer is:
`15.95`
Here ` u = 20 m s^(-1) , theta = 60^(@) , t = 0 . 5 s `
`v_(x) = u cos theta = 20 cos 60^(@) = 10 ms^(-1)`
`v_(y) = u sin theta - g t = 20 sin 60^(@) - 9 . 8 xx 0.5 `
`= 12 . 42 ms^(-1)`
`:. v = sqrt( v_(x)^(2) + v_(y)^(2))= sqrt((10) ^(2) + (12 . 42)^(2))`
`= 15 . 95 ms^(-1)`
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