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For a particle in uniform circular motio...

For a particle in uniform circular motion , the acceleration ` vec(a)` at a point ` p ( R, theta )` on the circle of radiu ` R` is ( Here ` theta` is measured from the ` x- axis` )

A

` ( v^(2))/( R) hat(i) + (v^(2))/( R) hat(j)`

B

`- (v^(2))/( R) cos theta hat(i)+ ( v^(2))/( R) sin theta hat(j)`

C

` - (v^(2))/( R) sin theta hat(i) + ( v^(2))/( R) cos theta hat(j)`

D

` - ( v^(2))/( R) cos theta hat(i) - (v^(2))/( R) sin theta hat(j)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vec (a) = ( - v^(2))/( R) cos theta hat(i) - (v^(2))/( R) sin theta hat (j)`
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