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A particle is moving along a circular pa...

A particle is moving along a circular path with a constant speed `10 ms^-1`.What is the magnitude of the change in velocity of the particle ,when it moves through an angle of `60^@` around the center of the circle ?

A

Zero

B

10m/s

C

`10 sqrt(2) m//s`

D

`10 sqrt(3) m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
` | Delta vec (V)| = 2 v sin"" (theta)/(2) = 2 v sin 30^(@) = 2 xx 10 xx (1)/(2) = 10 m//s `
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