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A particle is projected with speed u at ...

A particle is projected with speed u at angle `theta` with horizontal from ground . If it is at same height from ground at time `t_(1) and t_(2)` , then its average velocity in time interval `t_(1)` to `t_(2)` is

A

R/2 g

B

R / 4g

C

R/g

D

2R/g

Text Solution

Verified by Experts

The correct Answer is:
D
` t_(1) = (2 u sin theta_(1))/( g) , t_(2) = (2 u sin theta _(2))/(g)`
`t_(1) t_(2) = ( 4 u^(2))/(g^(2)) sin theta _(1) sin theta _(2) :. ` Ranges are equal
`theta_(2) = 90 - theta_(1) :. t_(1) t_(2) = (2)/(g) ( 2 u^(2) sin theta_(1) cos theta _(1))/(g) = (2 R)/(g)`
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