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A particle is projected horizontally wit...

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle `theta=37^(@)` to the horizontal `(g=10m//s^(2))`

Find the time taken by the particle to hit the plane.

A

18 cm

B

14 cm

C

26 cm

D

20 cm

Text Solution

Verified by Experts

The correct Answer is:
D
On inclined plane (range ) R `= ( 2U ^(2) sin alpha cos ( alpha + beta ))/( g cos ^(2) beta )`
Where ` alpha = 15^(@) , beta = 30^(@) , U = 2m//s`
On solving we get
`R = (4)/( 5) ((1)/( sqrt(3)) - (1)/( 3)) ~~ 20 cm`
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