Home
Class 11
PHYSICS
A body of mass 5 kg is suspended by a sp...

A body of mass 5 kg is suspended by a spring balance on an inclined plane as shown in figure. The spring balance measure

A

50 N

B

25 N

C

500 N

D

10 N

Text Solution

Verified by Experts

The correct Answer is:
B

Spring balance measure,`F = mg sin 30 = 5 xx 10 xx (1)/(2)` = 25N
Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass 10 kg is suspended throug two light spring balances as shown in figure

A body of mass 8 kg is suspended through two light springs X and Y connected in series as shown in figure. The readings is X and Y respectively are :

A block of mass 10 kg is suspended through two light spring balance as shown below:

A body of mass 50 kg is suspended using a spring balance inside a lift at rest. If the lift startts falling freely, the reading of the spring balance is

A block of mass 20 kg is suspended through two light spring balances as shown in fig. Calculate the: (a) reading of spring balance (1), (b) reading of spring balance (2).

A body of mass 30kg is hung by a spring balance in a lift. What would be the reading of the balance when the lift is (i) descending with a constant velocity of 5m//s (ii) ascending with a constant velocity of 10m//s .

A block of mass 4 kg and volume 5xx10^(-4) m^(3) is suspended by a spring balance in a lift which is accelerating. The apparent weight shown by the spring balance is 3 kg. Now the block is immersed in water in kg shown by the spring balance is