Home
Class 11
PHYSICS
A block of mass m is placed on a smooth...

A block of mass m is placed on a smooth wedge of inclination `theta`. The whole system is accelerated horizontally, so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

A

`mg cos theta`

B

`mg sin theta`

C

mg

D

mg/cos `theta`

Text Solution

Verified by Experts

The correct Answer is:
D
m g sin `theta = ma cos theta`
`rArr a = (g sin theta)/( cos theta)`
Force exerted by the wedge on block – R = mg cos `theta` + ma sin `theta` = mg cos `theta + m xx (g sin theta)/( cos theta) . Sin theta `
`R = (mg)/( cos theta)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass m is placed on a smooth wedge of incination theta . The whole system s acelerated horizontally so tht the block does not slip on the wedge. The force exerted by the wedge on the block has a magnitude

A block of mass m is placed on a smooth wedge of wedge angle theta The whole system is accelerated horizontally so that the block does not slip on the wedge. The force (normal reaction) exerted by the wedge on the block has a magnitude:

A block of mass m is placed on a smooth wedge of inclination. The whole system is accelerated horizontally so that block does not slip on the wedge Find the i) Acceleration of the wedge Force to be applied on the wedge Force exerted by the wedge on the block .

A block of mass m is placed on a smooth wedge of inclination theta . The while system is acceleration horizontally so that the block does not slip. Find (a) horizontal acceleration, (b) normal force between the block and the wedge and (c) the horizontal force applied on the wedge.

A block of mass m is kept on an inclined plane of mass 2m and inclination alpha to horizontal. If the whole system is accelerated such that the block does not slip on the wedge then :

A block of mass m is placed on a smooth wedge of inclination theta & mass M. The whole system is slip on the wedge. Then the normal reaction on the wedge acting from the ground :

Block of mass m is stationary w.r.t. wedge. Normal force exerted by wedge on the block is

A block mass 'm' is placed on a frictionless inclined plane of inclination theta with horizontal. The inclined plane is accelerated horizontally so that the block does not slide down. In this situation vertical force exerted by the inclined plane on the block is:

A block of mass m is placed on a smooth inclined plane of inclination theta with the horizontal. The force exerted by the plane on the block has a magnitude

A block of mass m is placed on a smooth slope of angle theta .The whole system (slope + block) is moved horizontally with acceleration a in such way that the block does not slip on the slope.Hence a = ________.