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A particle of mass 2 kg is initially at ...

A particle of mass 2 kg is initially at rest. A force , acts on it whose magnitude changes with time. The force-time graph is of shown here.
The velocity of the particle after 10 s is

A

`20 ms^(-1)`

B

`10 ms^(-1)`

C

`75 ms^(-1)`

D

`26 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Change in momentum = Impulse = area under F – t graph
`rArr mv =(1)/(2) xx 2 xx 10 + 2 xx 10 + (1)/(2) xx 2(10+20) + (1)/(2) 44 xx 20 `
` = 10 + 20 + 30 + 40 = 100`
`v =(100)/(2) = 50 m//s`
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