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A block of mass M placed on a frictionle...

A block of mass M placed on a frictionless horizontal table is pulled by another block of mass m hanging vertically by a massless string passing over a frictionless pulley. The tension in the string is :

A

`(m)/(M+m)g`

B

`(M)/(M+m)g`

C

`(M+m)/(Mm)g`

D

`(Mm)/(M+m)g`

Text Solution

Verified by Experts

The correct Answer is:
D

`T = m xx a = M xx ((mg)/(M + m)) = (Mmg)/(M + m)`
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