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Four blocks of the same mass m connected...

Four blocks of the same mass m connected by cords are pulled by a force F on a smooth horizontal surface as shown in Determine the tensions `T_1 ,T_2` and `T_3` in the cords.

Text Solution

Verified by Experts

The correct Answer is:
0.75

Let a be the common acceleration of the system Then,
`F =(m + m + m+ m)a = 4ma` or `a = F/(4m)`
Applying Newton.s 2nd law separately for each block in Figure, we get
`F -T_(1) = mg, T_(1) -T_(2) = ma, T_(2) - T_(3) = ma`
On solving the above equations, we get
`T_(1)= 3/4 F, T_(2) =1/2 F, T_(3) =1/4 F`, So `T_(1) = 0.75 F`
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