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Two fixed frictionless inclined plane ma...

Two fixed frictionless inclined plane making angles `30^(@)` and `60^(@)` with the vertical are shown in the figure. Two blocks A and B are placed on the two planes What is the relative vertical acceleration of A with respect to B ?

A

`4.9 ms^(-2)` in vertical direction

B

`4.9 ms^(-2)` in horizontal direction

C

`9.8 ms^(-2)` in vertical direction

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
A
`mg sin theta = ma`
`rArr a = g sin theta` where a is along the inclined planes
`therefore` Vertical component of acceleration is `g sin^(2) theta`
Relative vertical acceleration of A w.r.t B
`g(sin^(2)60 -sin^(2) 30) = g/2 = 4.9 m//s^(2)` (in vertical direction)
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