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If the interatomic spacing in a steel wi...

If the interatomic spacing in a steel wire is `3.0 Å and Y_(steel)=20xx10^(10)N//m^(2)` then force constant is

A

`6 xx 10^(-2) N//Å`

B

`6 xx 10^(-9) N//Å`

C

`4 xx 10^(-5) N//Å`

D

`6 xx 10^(-5) N//Å`

Text Solution

Verified by Experts

The correct Answer is:
B
`Y= (k)/(r_(0))=`
`rArr k= Y r_(0) = 20 xx 10^(10) xx 3 xx 10^(-10) = 60 N//m= (60N)/(10^(10) Å)= 6 xx 10^(-9) N//Å`
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