Home
Class 11
PHYSICS
The initail and final position vectors f...

The initail and final position vectors for a particle are respectively , `( - 3.0 m)hati + (2.0 m) hat j + (8.0 m ) hatk` and `(9.0 m)hati + (2.0 m )hatj + (- 8.0 m )hat k` . The displacement of the particle is

A

`(6.0m) hati + (4.0m) hatj + (16.0 m) hatk`

B

`(6.0m) hati`

C

`(12.0m) hati - (16.0 m)hatk`

D

`(12.0m) hati`

Text Solution

Verified by Experts

The correct Answer is:
C
Displacement vector = Final position – Initial position
`= (9 hati + 2 hatj- 8 hatk) - (-3 hati + 2hatj + 8 hatk)`
` = 12 hati - 16 hatk i.e (12.0m) hati - (16.0) hatk`
Promotional Banner

Similar Questions

Explore conceptually related problems

the initial and final and posdition vector for a particle are(-3) hati+(2m)hatj+(8m)hatk and (9m)hati+(2m) hatj+(-8m)hatk respectively ,find the displacement of the particle.

Let ABC be a triangle, the position vectors of whose vertices are respectively 7 hatj + 10 hatk , -hati + 6 hat j + 6 hatk and -4 hati + 9 hatj + 6 hat k . " Then, " Delta ABC is

The position vector for an electron is vecr=(6.0m)hati-(4.0m)hatj+(3.0m)hatk . (a) Find the magnitude of vecr .

The set of values of 'm' for which the vectors vec(a) = mhati + (m + 1)hatj +(m + 8)hatk vec(b) = (m + 3)hati + (m+4)hatj + (m +5) hatk and vec(c) = (m + 6)hati + (m + 7)hatj + (m + 8) hatk are non - coplanar is

Consider points A, B, C and D with position vectors 7 hati - 4 hat j + 7 hat k , hati - 6 hat j + 10 hat k , - hati - 3 hatj + 4 hatk and 5 hati - hatj + hatk respectively. Then, ABCD is a

Consider two vectors veca = (5.0) hati - (4.0) hatj + (2.0) hatk and vecb = (-2.0m) hati + ( 2.0)m hatj + (5. 0m) hatk, where m is a scalar. Find (a) veca + vecb , (b) veca - vecb , and (c ) a thirs vector vecc such that veca - vecb + vec c =0.

If a force of (8.0 hati+2.0 hatj+3 hatk)N displaces a body through a distance of (6.0 hati-3 .0 hatj -9 hatk) m . The work done will be

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

A machine carries a 4.0 kg package from an initial position of vec(d)_(i)=(0.50 m)hat(i)+(0.75 m)hat(j)+(0.20 m)hat(k) at t=0 to a final position of vec(d)_(f)=(7.50 m)hat(i)+(12.0 m) hat(k) at t=12 s. The constant force applied by the machine on the package is vec(F)= (2.00 N) hat(i) + (4.00 N) hat(j) + (6.00 N) hat(k) . For that displacement, find (a) the work done on the package by the machine's force and (b) the average power of the machine's force on the package.

Velocity and acceleration of a particle at time t = 0 are u=(2hat(i)+3hat(j))m//s and a=(4hat(i)+2hat(j))m//s^(2) respectively. Find the velocity and displacement of particle at t = 2 s.