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A man walks on a straight road form his ...

A man walks on a straight road form his home to a market 2.5 km away with speed of 5 `(km)/(hr)`. Finding the market closed, he instantly turns and walks back home with a speed of 7.5 `(km)/(hr)`. The average speed of the man over the intervel of time 0 to 40 min is equal to

A

5 km/h

B

`25/4` km/h

C

`30/4` km/h

D

`45/8` km/h

Text Solution

Verified by Experts

The correct Answer is:
D
Time to reach market `= (2.5km)/(5) = 1/2hr`
Distance travel (return back) = 7.5 xx 10/60`
`1 = 1.25 km`
`v_(avg) = (2.5+1.25)/(40//60) = 45/8 km//hr`
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