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A car moves a distance of 200m. It cover...

A car moves a distance of 200m. It covers first half of the distance at speed `60kmh^(-1)` and the second half at speed v. If the average speed is `40kmh^(-1)`, the value of v is

A

`30kmh^(-1)`

B

`13 kmh^(-1)`

C

`60kmh^(-1)`

D

`40kmh^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`v_(avg) = (200)/(100/60 + (100)/(v) ) rArr 40 = (200xx60xxv)/(100v+ 6000)`
`400v + 24000 = 1200v`
`v = (2400)/(800) = 30km//hr`
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