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If a car at rest, accelerates uniformly ...

If a car at rest, accelerates uniformly to a speed of `144 km//h` in `20s`, it covers a distance of

A

20 m

B

400 m

C

1440 m

D

2880 m

Text Solution

Verified by Experts

The correct Answer is:
B
`a = (144 xx 5/18)/(20) = (v-u)/(t)`
`rArr a = 40/20 = 2m//s^2`
Distance covers-
`S = ut + 1/2 at^2 = 1/2 xx 2 xx (20)^2 = 400m`
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