Home
Class 11
PHYSICS
A body starting from rest moves with con...

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5 sec is

A

`9//25`

B

`3//5`

C

`25//9`

D

`1//25`

Text Solution

Verified by Experts

The correct Answer is:
A
Distance covered in 5th second
`S_(5th) = u + a/2 (2xx5-1) = (9a)/(2)`
Distance covered in 5 sec –
`S_5 ut + 1/2 at^2 = (25a)/(2)`
`therefore (S_(5th))/(S_5) = 9/25`
Promotional Banner

Similar Questions

Explore conceptually related problems

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th second to that covered in 5 seconds is

A body starts from rest and moves with constant acceleration. The ratio of distance covered by the body in nth second to that covered in n second is.

A body starting from rest moves with constant acceleration. What is the ratio of distance covered by the body during the fifth second of time to that covered in the first 5.00 s ?

A bus starts from rest and moves whith acceleration a = 2 m/s^2 . The ratio of the distance covered in 6^(th) second to that covered in 6 seconds is

A body starts from rest and then moves with uniform acceleration. Then.

A body starts from rest with a uniform acceleration ‘a'. Find the distance covered by the body in nth second.

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

A body starts from rest, what is the ratio of the distance travelled by the body during the 4th and 3rd s?

A body starts from rest. What is the retio of the distance traveled by the body during the 4^(th) and 3^(rd) seconds