Home
Class 11
PHYSICS
A body starts from rest, what is the rat...

A body starts from rest, what is the ratio of the distance travelled by the body during the 4th and 3rd s?

A

`7//5`

B

`5//7`

C

`7//3 `

D

`3//7`

Text Solution

Verified by Experts

The correct Answer is:
A
Distance travelled in nth second –
`S_n = u+a/2 (2 n-1) = a/2 (2n - 1)`
`S_4/S_3 = (7a//2)/(5a//2) = 7/5`
Promotional Banner

Similar Questions

Explore conceptually related problems

A body starts from rest, if the ration of the distance travelled by the body during the 4th and 3rd second is x/5 . Find the valud of x.

A body starts from rest. What is the retio of the distance traveled by the body during the 4^(th) and 3^(rd) seconds

A body starts from rest. What is zero ?

A body starts from rest with a uniform acceleration ‘a'. Find the distance covered by the body in nth second.

A body starting from rest moves with constant acceleration. What is the ratio of distance covered by the body during the fifth second of time to that covered in the first 5.00 s ?

A body thrown vertically upwards with an initial valocity u reaches maximum height in 6 s. The ratio of the distances traveled by the body in the first second the seventh second is

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th second to that covered in 5 seconds is

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5 sec is

A body starts from rest and moves with constant acceleration. The ratio of distance covered by the body in nth second to that covered in n second is.