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A stone is dropped from a height h. Simu...

A stone is dropped from a height h. Simultaneously, another stone is thrown up from the ground which reaches a height 4 h. The two stones cross each other after time

A

`sqrt( (h)/(8g))`

B

`sqrt(8gh)`

C

`sqrt(2gh)`

D

`sqrt((h)/(2g))`

Text Solution

Verified by Experts

The correct Answer is:
A

For first stone u = 0
For second stone `(u^2)/(2g) = 4h rArr u^2 = 8gh`

` therefore u = sqrt(8gh)`
Now `h_1 = 1/2 g t^2`
`h_2 = sqrt(8ght) - 1/2 g t^2`
where, t =time to cross each other.
`because h_1 + h_2 = h`
`rArr 1/2 g t^2 + sqrt(8ght) - 1/2 g t^2 = h rArr t = (h)/(sqrt(8gh)) = sqrt( (h)/(8g))`
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