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A point initially at rest moves along x-...

A point initially at rest moves along x-axis. Its acceleration varies with time as `a = (6t + 5) m//s^(2)`. If it starts from origin, the distance covered in 2 s is:

A

20m

B

18m

C

16m

D

25m

Text Solution

Verified by Experts

The correct Answer is:
B
a = 6t + 5
`rArr (dv)/(dt) = 6t + 5`
`rArr v = (6t^2)/(2) + 5t = 3t^2 + 5t`
`rArr (dx)/(dt) = 3t^2 + 5t rArr x = 3 xx (t^3)/(3) + (5t^2)/(2)`
`x_(t=2) = 8 + 10 = 18m`
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