The displacement of a particle is given ...

The displacement of a particle is given by `y = a + bt + ct^2 - dt^4`. The initial velocity and acceleration are respectively.

A

`b- 4d`

B

`-b,2c`

C

`b,2c`

D

`2c,-4d`

Verified by Experts

The correct Answer is:

C

`y = a + bt + ct^2 -dt^4`
`v = (dy)/(dt) = b + 2ct - 4dt^3`
at t = 0, v = b
`a = (dv)/(dt) = 2c - 12t^2`
at t = 0, a = 2c

Similar Questions

Explore conceptually related problems

The displacement of a particle si given by y = a+bt +ct^(2) +dt^(4) .find the acceleration of a particle.

The displacement s of a particle at a time t is given bys =t^(3)-4t^(2)-5t. Find its velocity and acceleration at t=2 .

The displacement of a particle moving along x-axis is given by : x = a + bt + ct^2 The acceleration of the particle is.

The displacement of a moving particle is given by, x=at^3 + bt^2 +ct + d . The acceleration of particle at t=3 s would be

If reation between distance and time is s =a + bt + ct ^(2) find initial velocity and acceleratin

The displacement of a particle moving along a straight line is given by s=3t^(3)+2t^(2)-10t. find initial velocity and acceleration of particle.

If the displacement of a moving particle is given by s=5 + 20 t-2t^(2), then acceleration when velocity is zero, is

The acceleration of a particle is given by a = 3t and at t = 0, v = 0, x = 0. The velocity and displacement at t = 2 sec will be-

The displacement of a particle is given by x=At^(3)+Bt^(2)+Ct+D . The dimension of L in (AD)/(BC) will be

The displacement of a particle moving in a straight line is given by s=t^(3)-6t^(2)+3t+4 meters.The velocity when acceleration is zero is "