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The position x of a particle varies with...

The position x of a particle varies with time t as x=at^(2)-bt^(3) .The acceleration of the particle will be zero at time t equal to

A

a/b

B

`(2a)/(3b)`

C

`(a)/(3b)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
`x = at^2 - bt^3`
`rArr v = (dx)/(dt) = 2at - 3bt^2`
`rArr a = (dv)/(dt) = 2a - 6bt = 0 rArr t = (a)/(3b)`
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