Home
Class 11
PHYSICS
The distance travelled ‘S’ by an acceler...

The distance travelled ‘S’ by an accelerated particle of mass M is given by the following relation (in MKS units)
`S = 6t + 3t^2`
The velocity of the particle after 2 seconds is

A

6

B

12

C

18

D

24

Text Solution

Verified by Experts

The correct Answer is:
C
`S = 6t + 3t^2`
`rArr v = (dS)/(dt) = 6+6t`
at t = 2, v = 18m/s
Promotional Banner

Similar Questions

Explore conceptually related problems

Distance travelled by particle at any time t is given by S=t^(2)+6t+8 Speed of particle at any time t is

If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is

the distance s meters travelled in time t second by a car is given by the relation s=3t^(2) then find the velocity of the car at time ^(~ )t=4 seconds.

The distance s travelled by a particle moving on a straight line in time t sec is given by s=2t^(3)-9t^(2)+12t+6 then the initial velocity of the particle is

The distance covered by a particle in t second is given by x=3+8t-4t^(2) . After 1s its velocity will be

The displacment of a particle is represented by the following equation : s=3t^(3)+7t^(2)+5t+8 where s is in metre and t in second. The acceleration of the particle at t=1:-

If displacement of particle is s=t^(3)-6t^(2)+9t+15, then velocity of the particle at beginning is

The horizontal and vertical distances travelled by a particle in time t are given by x=6t and y=8t-5t^(2) . If g= 10m//sec^(2) , then the initial velocity of the particle is