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The position of a particle x (in meters)...

The position of a particle x (in meters) at a time t seconds is given by the relation `vecr = (3t hati - t^2 hatj + 4 hatk)`. Calculate the magnitude of velocity of the particle after 5 seconds

A

3.55

B

5.03

C

8.75

D

10.44

Text Solution

Verified by Experts

The correct Answer is:
D
Position `vecr = 3 t hati - t^2 hatj + 4 hatk`
`vec v = (dvecr)/(dt) = 3hati -2hatj`
at t = 5sec, `vecv = 3hati - 10 hatj`
`|vecv| = sqrt(3^2 + (-10)^2) = sqrt109 = 10.44 m//s`
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