If the velocity of a particle is given b...

If the velocity of a particle is given by `v=(180-16x)^((1)/(2))(m)/(s)`, then its acceleration will be

A

zero

B

`8 m//s^2`

C

`-8 m//s^2`

D

`4 m//s^2 `

Verified by Experts

The correct Answer is:

C

`v = (180 - 16x )^(1/2)`
`a = (dv)/(dt) = 1/2 (180 - 16x)^(1/2 - 1) (-16) (dx)/(dt)`
`= (-8)/((180-16x)^(1/2)) xx (180 - 16x)^(1/2) = -8m//s^2`

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