Home
Class 11
PHYSICS
A particle move a distance x in time t a...

A particle move a distance `x` in time `t` according to equation `x = (t + 5)^-1`. The acceleration of particle is alphaortional to.

A

`v^(2//3)`

B

`v^(3//2)`

C

`d^2`

D

`d^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`x = (t+5)^(-1)`
`rArr v = (dx)/(dt) = -1 (t + 5)^(-2) rArr a = (dv)/(dt) = 2(t + 5)^(-3)`
`rArr 2(t + 5)^(-2) xx (t + 5)^(-1)`
`rArr 2 (-v) xx (-v)^(1/2) rArr 2(-v)(3/2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves a distance x in time t according to equation x=(t+5)^(-1) . The acceleration of particle is proportional to

A particle moves a distance x in time t according to equation x^(2) = 1 + t^(2) . The acceleration of the particle is

A particle moves in x-y plane according to equations x = 4t^(2)+5t and 6y=5t The acceleration of the particle must be

A particle is moving along+x aixes according to equation x= 5(1-e^(-2t)

A particle moves according to the equation t = ax^(2)+bx , then the retardation of the particle when x = (b)/(a) is

A particle moves on the x -axis according to the equation x=x_(0)sin2 omega t .The motion is simple harmonic ?

A particle moves in the x-y plane according to the law x=t^(2) , y = 2t. Find: (a) velocity and acceleration of the particle as a function of time, (b) the speed and rate of change of speed of the particle as a function of time, (c) the distance travelled by the particle as a function of time. (d) the radius of curvature of the particle as a function of time.

A particle moves according to equation x = A cos pi t . The distance covered by it in 3.5 s is

A particle moves according to the equation x= a cos pi t . The distance covered by it in 2.5 s is