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A particle of unit mass undergoes one-di...

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to
`v(x) = beta x^(-2 n)`
where `beta` and `n` are constant and `x` is the position of the particle. The acceleration of the particle as a function of `x` is given by.

A

`(-2nb^2 x^(-4n-1)`

B

`-2b^2 x^(-2n+1)`

C

`(-2nb^2 e^(-4n+1)`

D

`-2nb^2 x^(-2n-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`v(x) = bx^(-2n)`
`a = v (dv)/(dx) = bx^(-2n) {b (-2n)x^(-2n - 1) ) = -2b^2 nx^(-4n - 1)`
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