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Particle A moves along X-axis with a uni...

Particle A moves along X-axis with a uniform velocity of magnitude 10 m/s. Particle B moves with uniform velocity 20 m/s along a direction making an angle of 60° with the positive direction of X-axis as shown in the figure. The relative velocity of B with respect to that A is

A

10 m/s along X-axis

B

`10sqrt3` m/s along Y-axis (perpendicular to X-axis)

C

`10sqrt5`along the bisection of the velocity of A and B

D

30 m/s along negative X-axis

Text Solution

Verified by Experts

The correct Answer is:
B
`vec(V_(BA)) = vecV_B - vecV_A`
` = (20 xx cos 60^@ hati + 20 sin 60^@ hatj) - 10 hati = 10 sqrt3 hatj`
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