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Two bodies of different masses m(a) and ...

Two bodies of different masses `m_(a)` and `m_(b)` are dropped from two different heights a and b. The ratio of the time taken by the two to cover these distances are

A

`a:b`

B

`b:a`

C

`sqrta : sqrtb`

D

`a^2 : b^2`

Text Solution

Verified by Experts

The correct Answer is:
C
`t = sqrt((2h)/(g)) ` Since ` t prop sqrth`
`t_1/t_2 = sqrta/sqrtb`
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