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A particle is thrown vertically upwards....

A particle is thrown vertically upwards. If its velocity at half of the maximum height is 10 m/s, then maximum height attained by it is

A

8m

B

10m

C

12m

D

16m

Text Solution

Verified by Experts

The correct Answer is:
B
`v^2 = u^2 - 2gh`
`rArr 10^2 = u^2 - 2 xx 10 xx H/2`
Since, `H = (u^2)/(2g)`
`100 = u^2 - 2 xx 10 xx (u^2)/(4g) rArr u^2 = 200 rArr u = 10 sqrt2m//s`
`H = (u^2)/(2g) = (200)/(2xx10) = 10m`
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