Home
Class 11
PHYSICS
A ball is dropped from top of a tower of...

A ball is dropped from top of a tower of 100 m height. Simultaneously another ball was thrown upward from bottom of the tower with a speed of `50 m//s (g = 10m//s^(2))`. They will cross each other after

A

1s

B

2s

C

3s

D

4s

Text Solution

Verified by Experts

The correct Answer is:
B
`h_1 = 1/2 g t^2`
`h_2 = 50t - 1/2 g t^2`
`h_1 + h_2 = 100 rArr 50t = 100 rArr t = 2sec`
Promotional Banner

Similar Questions

Explore conceptually related problems

A stone is dropped from the top of a 400 m high tower. At the same time another stone is projected vertically upwards from the ground with a speed of 50 m//s . The two stones will cross each other after a time

A ball is dropped from top of a tower 250 m high. At the same time, another ball is thrown upwards with a velocity of 50 ms^(-1) from the ground. The time at which they cross each other is

A wooden block of mass 10 g is dropped from the top of a tower 100 m high. Simultaneously, a bullet of mass 10 g is fired from the foot of the tower vertically upwards with a velocity of 100 m//s . If the bullet is embedded in it, how high will the block rise above the top of tower before it starts falling? (g=10m//s^2)

A ball is dropped from the top of an 80 m high tower After 2 s another ball is thrown downwards from the tower. Both the balls reach the ground simultaneously. The initial speed of the second ball is

A ball A is dropped from a building of height 45 m . Simultaneously another ball B is thrown up with a speed 40 m//s . Calculate the relative speed of the balls as a function of time.

A ball is thrown downwards with a speed of 20 ms^(–1) from top of a building 150m high and simultaneously another ball is thrown vertically upwards with a speed of 30 ms^(–1) from the foot of the building. Find the time after which both the balls will meet - (g = 10 ms^(–2))